QUESTION IMAGE
Question
find the measure of the missing angles.
Step1: Find angle \( h \)
Angles \( h \) and \( 93^\circ \) are supplementary (form a linear pair), so \( h + 93^\circ = 180^\circ \).
\( h = 180^\circ - 93^\circ = 87^\circ \)
Step2: Find angle \( g \)
Angles \( g \) and \( 93^\circ \) are vertical angles? No, \( g \) and \( h \) are vertical? Wait, \( h \) and \( g \): Wait, the horizontal line and vertical line intersect, so \( h \) and the angle opposite to \( 93^\circ \)? Wait, no, \( h \) and \( 93^\circ \) are adjacent, forming a linear pair. Then \( g \) is vertical to \( 93^\circ \)? Wait, no, the vertical line and horizontal line intersect, so \( h + 93^\circ = 180^\circ \) (linear pair), and \( g \) is vertical to \( 93^\circ \)? Wait, no, \( g \) and \( h \) are adjacent? Wait, maybe I made a mistake. Wait, the vertical line and horizontal line: so the angle \( h \) and \( 93^\circ \) are adjacent, sum to \( 180^\circ \), so \( h = 87^\circ \). Then \( g \) is vertical to \( 93^\circ \)? No, \( g \) is adjacent to \( h \), forming a linear pair? Wait, no, the vertical line is straight, so \( h + 93^\circ = 180^\circ \), and \( g \) is equal to \( 93^\circ \)? Wait, no, vertical angles: when two lines intersect, vertical angles are equal. Wait, the horizontal line and vertical line intersect, so the angle \( h \) and the angle opposite to \( 93^\circ \) (let's say angle \( x \)) are vertical? No, \( h \) and \( 93^\circ \) are adjacent, so \( h = 180 - 93 = 87 \). Then \( g \) is vertical to \( 93^\circ \)? Wait, no, \( g \) is adjacent to \( h \), so \( g + h = 180^\circ \)? No, the vertical line is straight, so the sum of angles on a straight line is \( 180^\circ \). Wait, maybe \( g \) is equal to \( 93^\circ \)? No, that can't be. Wait, let's re-examine. The horizontal line and vertical line intersect, creating four angles. \( h \) and \( 93^\circ \) are adjacent, so they are supplementary. So \( h = 180 - 93 = 87^\circ \). Then \( g \) is vertical to \( 93^\circ \)? No, \( g \) is vertical to \( h \)? Wait, no, vertical angles: when two lines intersect, opposite angles are equal. So the angle opposite to \( h \) is \( 93^\circ \), and the angle opposite to \( 93^\circ \) is \( h \). Wait, no, that's not right. Wait, if \( h \) and \( 93^\circ \) are adjacent, then \( h + 93 = 180 \), so \( h = 87 \). Then the angle opposite to \( h \) is \( 93^\circ \), and the angle opposite to \( 93^\circ \) is \( h = 87^\circ \). Wait, maybe \( g \) is equal to \( 93^\circ \)? No, I think I messed up. Wait, the vertical line is straight, so the angle \( g \) and \( h \) are adjacent, forming a linear pair? No, the horizontal line is straight, so \( h + 93 = 180 \), so \( h = 87 \). Then the vertical line: the angle \( g \) is adjacent to \( h \), so \( g + h = 180 \)? No, the vertical line is straight, so the sum of angles on the vertical line? Wait, no, the horizontal line is horizontal, vertical line is vertical, so they intersect at a point, forming four angles: \( h \), \( 93^\circ \), \( g \), and the angle opposite to \( h \). So \( h + 93 = 180 \) (linear pair), so \( h = 87 \). Then \( g \) is equal to \( 93^\circ \) (vertical angle to \( 93^\circ \))? Wait, no, vertical angles are opposite. So \( h \) and the angle opposite to \( 93^\circ \) are vertical? No, let's label the intersection: horizontal line (left-right) and vertical line (up-down) intersect at a point. Let's call the intersection point O. The angle between vertical line (up) and horizontal line (right) is \( 93^\circ \), so angle \( \angle AOB = 93^\circ \), where A is up, B is right. Then angle \( \an…
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- \( h = 87^\circ \)
- \( g = 93^\circ \)
- \( m = 58^\circ \)
- \( k = 122^\circ \)