QUESTION IMAGE
Question
find the missing number so that the equation has infinitely many solutions. -2(-x - 3) = 2x + \square
Step1: Expand left-hand side
$
-2(-x - 3) = (-2)(-x) + (-2)(-3)
$
Step2: Calculate the products
$
(-2)(-x) + (-2)(-3) = 2x + 6
$
Step3: Match for infinite solutions
For the equation $2x + 6 = 2x + \square$ to have infinitely many solutions, the constant terms must be equal.
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