Question

find the perimeter and total area of the polygon shape shown below. all measurements are given in inches. perimeter = 68 inches, area = 192 square inches perimeter = 68 inches, area = 240 square inches perimeter = 56 inches, area = 192 square inches perimeter = 56 inches, area = 204 square inches

Explanation:

Step1: Calculate the perimeter

Add up the lengths of all sides. There are 3 sides of length 12 and 2 sides of length 10.
$12\times3 + 10\times2=36 + 20=56$ inches

Step2: Calculate the area

The shape is composed of a square and a triangle. Area of square with side - length 12 is $A_{square}=12\times12 = 144$ square inches. Area of triangle with base 12 and height 8 is $A_{triangle}=\frac{1}{2}\times12\times8=48$ square inches. Total area $A = A_{square}+A_{triangle}=144 + 48=192$ square inches

Answer:

Perimeter = 56 inches, Area = 192 square inches