Question

find the solution to the system of equations by substitution.
p = q + 2
2p + 4q = -26
the solution is \\(\square\\).
(simplify your answer. type an ordered pair.)

Explanation:

Step1: Substitute p into second equation

Substitute $p = q + 2$ into $2p + 4q = -26$:
$2(q + 2) + 4q = -26$

Step2: Expand and simplify

Expand the left side:
$2q + 4 + 4q = -26$
Combine like terms:
$6q + 4 = -26$

Step3: Solve for q

Subtract 4 from both sides:
$6q = -26 - 4 = -30$
Divide by 6:
$q = \frac{-30}{6} = -5$

Step4: Solve for p

Substitute $q = -5$ into $p = q + 2$:
$p = -5 + 2 = -3$

Answer:

$(-3, -5)$