QUESTION IMAGE
Question
find the value of the missing sides. leave in rationalized and simplified form.
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Step1: Recall 45 - 45 - 90 triangle ratio
In a 45 - 45 - 90 triangle, the ratio of the sides is $a:a:a\sqrt{2}$, where $a$ is the length of each of the legs and $a\sqrt{2}$ is the length of the hypotenuse.
Step2: Solve for each triangle
For triangle 1:
The legs are 17. Using the hypotenuse formula $h = a\sqrt{2}$, with $a = 17$, the hypotenuse $x=17\sqrt{2}$.
For triangle 2:
The hypotenuse $h = 2\sqrt{2}$. Since $h=a\sqrt{2}$, then $a\sqrt{2}=2\sqrt{2}$, so $a = 2$ (each leg is 2).
For triangle 3:
The leg $a = 4\sqrt{2}$. The hypotenuse $h=a\sqrt{2}=4\sqrt{2}\times\sqrt{2}=4\times2 = 8$.
For triangle 4:
The leg $a = 20$. The hypotenuse $h=a\sqrt{2}=20\sqrt{2}$.
For triangle 5:
The leg $a = 10\sqrt{2}$. The hypotenuse $h=a\sqrt{2}=10\sqrt{2}\times\sqrt{2}=20$.
For triangle 6:
The hypotenuse $h = 3\sqrt{6}$. Since $h=a\sqrt{2}$, then $a=\frac{3\sqrt{6}}{\sqrt{2}}=\frac{3\sqrt{6}\times\sqrt{2}}{\sqrt{2}\times\sqrt{2}}=\frac{3\sqrt{12}}{2}=\frac{3\times2\sqrt{3}}{2}=3\sqrt{3}$ (each leg is $3\sqrt{3}$).
For triangle 7:
The hypotenuse $h = 6$. Since $h=a\sqrt{2}$, then $a=\frac{6}{\sqrt{2}}=\frac{6\sqrt{2}}{2}=3\sqrt{2}$ (each leg is $3\sqrt{2}$).
For triangle 8:
The leg $a = 1$. The hypotenuse $h=a\sqrt{2}=\sqrt{2}$.
For triangle 9:
The leg $a = 12$. The hypotenuse $h=a\sqrt{2}=12\sqrt{2}$.
For triangle 10:
The leg $a = 5\sqrt{8}=5\times2\sqrt{2}=10\sqrt{2}$. The hypotenuse $h=a\sqrt{2}=10\sqrt{2}\times\sqrt{2}=20$.
For triangle 11:
The leg $a = 6\sqrt{8}=6\times2\sqrt{2}=12\sqrt{2}$. The hypotenuse $h=a\sqrt{2}=12\sqrt{2}\times\sqrt{2}=24$.
For triangle 12:
The leg $a = 9\sqrt{2}$. The hypotenuse $h=a\sqrt{2}=9\sqrt{2}\times\sqrt{2}=18$.
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- $x = 17\sqrt{2}$
- Legs: 2
- Hypotenuse: 8
- Hypotenuse: $20\sqrt{2}$
- Hypotenuse: 20
- Legs: $3\sqrt{3}$
- Legs: $3\sqrt{2}$
- Hypotenuse: $\sqrt{2}$
- Hypotenuse: $12\sqrt{2}$
- Hypotenuse: 20
- Hypotenuse: 24
- Hypotenuse: 18