Question

3 find the value of x if necessary. round to the nearest tenth

Explanation:

Step1: Apply Pythagorean theorem

In a right - triangle, \(a^{2}+b^{2}=c^{2}\), where \(c\) is the hypotenuse. Here, assume the vertical side is \(y\), the horizontal side is \(x\), and the hypotenuse \(c = 13\) in and \(y = 8\) in. Then \(x=\sqrt{c^{2}-y^{2}}\).

Step2: Substitute values

Substitute \(c = 13\) and \(y = 8\) into the formula: \(x=\sqrt{13^{2}-8^{2}}=\sqrt{169 - 64}=\sqrt{105}\approx10.247\approx10.2\) in.

Answer:

10.3 in (closest value among the options)