Question

find the value of a. pythagorean theorem: $a^{2}+b^{2}=c^{2}$ a 12 in 7 in $a = sqrt{?}$

Explanation:

Step1: Identify sides in Pythagorean theorem

Let $a$ be one leg, $b = 7$ in and $c=12$ in. According to $a^{2}+b^{2}=c^{2}$, we can solve for $a$.

Step2: Rearrange the formula

$a^{2}=c^{2}-b^{2}$. Substitute $b = 7$ and $c = 12$ into the formula: $a^{2}=12^{2}-7^{2}$.

Step3: Calculate the values

$12^{2}=144$ and $7^{2}=49$. So $a^{2}=144 - 49=95$.

Step4: Find the value of a

$a=\sqrt{95}$ in.

Answer:

$\sqrt{95}$ in