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find the value of x. round answers to the nearest tenth (one decimal pl…

Question

find the value of x. round answers to the nearest tenth (one decimal place). x =

Explanation:

Step1: Identify trigonometric ratio

In the right triangle, we have the hypotenuse (18) and we need to find the side opposite the 72° angle? Wait, no, x is adjacent? Wait, no, the right angle, the angle of 72°, so x is opposite? Wait, no, let's see: the right triangle has a right angle, a 72° angle, so the side x is opposite the 72° angle? Wait, no, the hypotenuse is 18, and x is one of the legs. Wait, actually, in the right triangle, the side x is adjacent to the 72° angle? Wait, no, let's label: the right angle is at the top, the 72° angle is at the left, so the hypotenuse is 18, the side x is opposite the 72° angle? Wait, no, the angle at the left is 72°, so the side opposite to 72° is the vertical leg, and x is the horizontal leg. Wait, no, let's use sine or cosine. Wait, the angle is 72°, the hypotenuse is 18, and x is the side opposite to the 72° angle? Wait, no, the right angle is between x and the vertical leg. So the angle of 72° is at the left, so the side adjacent to 72° is x? Wait, no, adjacent is next to the angle. So angle 72°: the sides are hypotenuse (18), adjacent (x), and opposite (vertical leg). Wait, no, cosine of 72° is adjacent over hypotenuse, so cos(72°) = x / 18? Wait, no, wait: if the angle is 72°, then the adjacent side is x, hypotenuse is 18, so cos(72°) = adjacent / hypotenuse = x / 18. Wait, no, maybe sine. Wait, let's think again. The right triangle: angle at left is 72°, right angle at top, so the sides: the side opposite 72° is the vertical leg, the side adjacent to 72° is x (horizontal leg), hypotenuse is 18. So to find x, we can use cosine: cos(theta) = adjacent / hypotenuse. So theta is 72°, adjacent is x, hypotenuse is 18. So x = 18 cos(72°)? Wait, no, wait, maybe sine. Wait, no, if the angle is 72°, and we want x, which is opposite? Wait, no, I think I made a mistake. Let's draw mentally: right angle at (0,0), 72° angle at (-1,0), hypotenuse from (-1,0) to (0,y), length 18. Wait, no, maybe better to use sine. Wait, the angle is 72°, so sin(72°) = opposite / hypotenuse. The opposite side to 72° is the vertical leg, and x is the horizontal leg. Wait, no, I'm confused. Wait, the problem is a right triangle with hypotenuse 18, angle 72°, find x (one leg). Let's use sine: sin(72°) = x / 18? Wait, no, if x is opposite the 72° angle, then yes. Wait, maybe the diagram is such that x is opposite the 72° angle. Wait, the right angle is at the top, so the two legs are x (horizontal) and vertical, hypotenuse 18. The angle at the bottom left is 72°, so the angle between the hypotenuse and the horizontal leg (x) is 72°, so the side opposite to 72° is the vertical leg, and x is adjacent. Wait, no, I think I need to use sine. Wait, let's calculate both. Let's check: cos(72°) ≈ 0.3090, sin(72°) ≈ 0.9511. So if x is adjacent, then x = 18 cos(72°) ≈ 18 0.3090 ≈ 5.562. If x is opposite, then x = 18 sin(72°) ≈ 18 0.9511 ≈ 17.12. But that seems too big. Wait, the diagram: the hypotenuse is 18, and x is a leg, so it should be smaller than 18. Wait, maybe the angle is 72°, and x is opposite, but that would make x almost 18, which is close to hypotenuse, which is possible? Wait, no, in a right triangle, the hypotenuse is the longest side. So if x is a leg, it must be less than 18. Wait, so if x is opposite 72°, then sin(72°) = x / 18 => x = 18 sin(72°) ≈ 18 * 0.9511 ≈ 17.1. But that's close to 18, which is possible. Wait, maybe I had the angle wrong. Wait, the angle is 72°, so the other angle is 18°, so the side opposite 18° would be smaller. Wait, maybe x is opposite 18°, but no, the angle given is 72°. Wa…

Answer:

17.1