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find the y-intercept, the axis of symmetry, and the vertex of the graph…

Question

find the y-intercept, the axis of symmetry, and the vertex of the graph of the function.\\( f(x) = -x^2 - 2x - 9 \\)\\( \\)\\( \\)the y-intercept is \\( \square \\). (type an ordered pair.)

Explanation:

Step1: Recall y-intercept definition

The y-intercept of a function \( f(x) \) is the point where \( x = 0 \), so we substitute \( x = 0 \) into the function.
\( f(0)=-(0)^{2}-2(0)-9 \)

Step2: Calculate \( f(0) \)

Simplify the expression: \( f(0)=0 - 0 - 9=-9 \). So the ordered pair is \( (0, -9) \).

Answer:

\((0, -9)\)