Question

find the zeros of the function. f(x)=3x^2 + 6 the zeros of f are x = and x =

Explanation:

Step1: Set the function equal to zero

$3x^{2}+6 = 0$

Step2: Isolate the $x^{2}$ - term

Subtract 6 from both sides: $3x^{2}=-6$. Then divide both sides by 3, getting $x^{2}=-2$.

Step3: Solve for $x$

Take the square - root of both sides. Since $\sqrt{-2}=\pm\sqrt{2}i$, then $x = \pm\sqrt{2}i$.

Answer:

$x=\sqrt{2}i$ and $x =-\sqrt{2}i$