QUESTION IMAGE
Question
finding angles
find the value of the labelled angles.
(a)
(b) 5.9 cm
(c) 2 cm
(d) 20 cm 5 cm
find the value of the labelled angles.
(e)
(f) 9 m 5 m
(g) 12.3 cm 5.8 cm
(h) 0.7 m 0.5 m
(i) 12.5 cm 9.4 cm
(j) 16.5 m 15.1 m
find the missing angles.
(k) 10 cm
Part (a)
Step 1: Identify the sides relative to angle \( x \)
In the right - triangle, the opposite side to \( x \) is \( 6\space\text{cm} \) and the adjacent side is \( 2\space\text{cm} \). We use the tangent function, where \( \tan(x)=\frac{\text{opposite}}{\text{adjacent}} \)
\( \tan(x)=\frac{6}{2} = 3 \)
Step 2: Find the angle
To find \( x \), we take the arctangent (inverse tangent) of 3. \( x=\arctan(3) \)
Using a calculator, \( x\approx71.57^{\circ} \)
Part (b)
Step 1: Identify the sides relative to angle \( x \)
In the right - triangle, the adjacent side to \( x \) is \( 4.6\space\text{cm} \) and the opposite side is \( 5.9\space\text{cm} \). We use the tangent function \( \tan(x)=\frac{\text{opposite}}{\text{adjacent}} \)
\( \tan(x)=\frac{5.9}{4.6}\approx1.2826 \)
Step 2: Find the angle
\( x = \arctan(1.2826) \)
Using a calculator, \( x\approx52.0^{\circ} \)
Part (c)
Step 1: Identify the sides relative to angle \( x \)
In the right - triangle, the opposite side to \( x \) is \( 8\space\text{m} \) and the hypotenuse is \( 10\space\text{m} \). We use the sine function \( \sin(x)=\frac{\text{opposite}}{\text{hypotenuse}} \)
\( \sin(x)=\frac{8}{10}=0.8 \)
Step 2: Find the angle
\( x=\arcsin(0.8) \)
Using a calculator, \( x\approx53.13^{\circ} \)
Part (d)
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Step 1: Identify the sides relative to angle \( x \)
In the right - triangle, the adjacent side to \( x \) is \( 15.1\space\text{m} \) and the hypotenuse is \( 16.5\space\text{m} \). We use the cosine function \( \cos(x)=\frac{\text{adjacent}}{\text{hypotenuse}} \)
\( \cos(x)=\frac{15.1}{16.5}\approx0.9152 \)
Step 2: Find the angle
\( x=\arccos(0.9152) \)
Using a calculator, \( x\approx24.0^{\circ} \)