Question

first we must set up our equ using the pythagorean the a² + b² = c² 4² + b² = 13² 16 + b² = 169 b² = ? hint: subtract the value of 16 from 169

Explanation:

Step1: Isolate $b^{2}$

We start with the equation $16 + b^{2}=169$. To isolate $b^{2}$, we subtract 16 from both sides of the equation.
$b^{2}=169 - 16$

Step2: Calculate the value

$169-16 = 153$. So, $b^{2}=153$.

Answer:

153