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Question
the floor of the cafeteria at valley view middle school has a v - shaped design as shown. each square in the diagram represents one tile. the side length of each tile is 8 inches. what is the area of the design? using a horizontal side as the base, the length of the base of each parallelogram is 2 × 8, or 16 inches. the height is 4 × 8, or 32 inches. what is the total area of both parallelograms? use the number pad to enter your answer in the box.
Step1: Calculate area of one parallelogram
The area formula for a parallelogram is $A = b\times h$. Given $b = 16$ inches (since $2\times8 = 16$) and $h=32$ inches (since $4\times8 = 32$), then $A_1=16\times32 = 512$ square - inches.
Step2: Calculate total area of two parallelograms
Since there are two identical parallelograms, the total area $A_{total}=2\times A_1$. So $A_{total}=2\times512 = 1024$ square - inches.
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