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Question
a flower bed is in the shape of a triangle with one side twice the length of the shortest side and the third side is 25 feet more than the length of the shortest side. find the dimensions if the perimeter is 141 feet. what is the length of the shortest side? the length of the shortest side is 29 feet. what is the length of the second side? the length of the second side is
Step1: Let the length of the shortest side be $x$.
The first - side is $2x$ (since one side is twice the length of the shortest side), and the third - side is $x + 25$ (since the third side is 25 feet more than the length of the shortest side).
Step2: Set up the perimeter equation.
The perimeter of a triangle is the sum of its sides. So, $x+2x+(x + 25)=141$.
Step3: Combine like - terms.
$(x+2x+x)+25 = 141$, which simplifies to $4x+25 = 141$.
Step4: Solve for $x$.
Subtract 25 from both sides: $4x=141 - 25=116$. Then divide both sides by 4: $x=\frac{116}{4}=29$.
Step5: Find the length of the second side.
The second side is $2x$. Substitute $x = 29$ into $2x$, we get $2\times29 = 58$.
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