Question

the formula for the volume of a cone is $v = \frac{1}{3}bh$. solve $v = \frac{1}{3}bh$ for $b$, the base of the cone. \\(\bigcirc\\) a. $b = \frac{3v}{h}$ \\(\bigcirc\\) b. $b = \frac{v}{3h}$ \\(\bigcirc\\) c. $b = \frac{h}{3v}$ \\(\bigcirc\\) d. $b = \frac{3h}{v}$

Explanation:

Step1: Multiply both sides by 3

To isolate the term with \( b \), we multiply both sides of the equation \( V = \frac{1}{3}bh \) by 3. This gives us \( 3V = bh \).

Step2: Divide both sides by \( h \)

Now, to solve for \( b \), we divide both sides of the equation \( 3V = bh \) by \( h \) (assuming \( h
eq 0 \)). So we get \( b = \frac{3V}{h} \).

Answer:

A. \( b = \frac{3V}{h} \)