Question

the function f is defined as follows.
$f(x)=\sqrt3{x + 1}$
find $f(-28)$ and $f(124)$.
$f(-28)=\square$
$f(124)=\square$

Explanation:

Step1: Calcular \( f(-28) \)

Sustituir \( x = -28 \) en \( f(x) = \sqrt[3]{x + 1} \).
\( f(-28) = \sqrt[3]{-28 + 1} = \sqrt[3]{-27} \)
Como \( (-3)^3 = -27 \), entonces \( \sqrt[3]{-27} = -3 \).

Step2: Calcular \( f(124) \)

Sustituir \( x = 124 \) en \( f(x) = \sqrt[3]{x + 1} \).
\( f(124) = \sqrt[3]{124 + 1} = \sqrt[3]{125} \)
Como \( 5^3 = 125 \), entonces \( \sqrt[3]{125} = 5 \).

Answer:

\( f(-28) = -3 \)
\( f(124) = 5 \)