QUESTION IMAGE
Question
- in garden peas, tall (t) vine is dominant over short (t) vine. yellow (y) seed color is dominant over green (y) seed color. cross a heterozygous tall, yellow seeded plant with a heterozygous tall, yellow seeded plant.
genotypes of the parent plants
genotypes | phenotypes
--- | ---
what is the probability for a tall offspring?
what is the probability for a short offspring?
what is the probability for a yellow offspring?
what is the probability for a green offspring?
what is the probability for a tall yellow offspring?
what is the probability for a tall green offspring?
what is the probability for a short yellow offspring?
Step1: Identify parent genotypes
Heterozygous tall, yellow plants have genotype $TtYy$ (both parents).
Step2: List gamete combinations
Each parent produces 4 gametes: $TY, Ty, tY, ty$.
Step3: Complete Punnett Square
Step4: Count genotype/phenotype totals
Total offspring combinations: 16
- Tall ($T\_$): 12 (all except $ttYY, ttYy, ttYy, ttyy$)
- Short ($tt$): 4
- Yellow ($Y\_$): 12 (all except $TTyy, Ttyy, Ttyy, ttyy$)
- Green ($yy$): 4
- Tall yellow ($T\_Y\_$): 9
- Tall green ($T\_yy$): 3
- Short yellow ($ttY\_$): 3
Step5: Calculate probabilities
Probability = $\frac{\text{Number of desired outcomes}}{\text{Total outcomes}}$
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Genotypes of the parent plants:
$TtYy$ and $TtYy$
Genotypes and Phenotypes:
| Genotypes | Phenotypes |
|---|---|
| $TTyy, Ttyy$ | Tall, green |
| $ttYY, ttYy$ | Short, yellow |
| $ttyy$ | Short, green |
Probabilities:
- Probability for a tall offspring: $\frac{12}{16} = \frac{3}{4}$
- Probability for a short offspring: $\frac{4}{16} = \frac{1}{4}$
- Probability for a yellow offspring: $\frac{12}{16} = \frac{3}{4}$
- Probability for a green offspring: $\frac{4}{16} = \frac{1}{4}$
- Probability for a tall yellow offspring: $\frac{9}{16}$
- Probability for a tall green offspring: $\frac{3}{16}$
- Probability for a short yellow offspring: $\frac{3}{16}$