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Question
give the coordinates of the point obtained from each reflection.
(a) reflect the point (-9, -6) across the x-axis: (□, □)
(b) reflect the point (-9, -6) across the y-axis: (□, □)
Part (a)
Step1: Recall reflection over x - axis rule
The rule for reflecting a point \((x,y)\) across the \(x\) - axis is \((x,-y)\).
Step2: Apply the rule to the point \((-9,-6)\)
Here, \(x=-9\) and \(y = - 6\). So, when we reflect across the \(x\) - axis, the new \(y\) - coordinate is \(-y=-(-6) = 6\) and the \(x\) - coordinate remains the same. So the reflected point is \((-9,6)\).
Part (b)
Step1: Recall reflection over y - axis rule
The rule for reflecting a point \((x,y)\) across the \(y\) - axis is \((-x,y)\).
Step2: Apply the rule to the point \((-9,-6)\)
Here, \(x = - 9\) and \(y=-6\). So, when we reflect across the \(y\) - axis, the new \(x\) - coordinate is \(-x=-(-9)=9\) and the \(y\) - coordinate remains the same. So the reflected point is \((9,-6)\).
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(a) \((-9, 6)\)
(b) \((9, -6)\)