Question

given: abcd is a parallelogram and e is the midpoint of \\(\overline{bc}\\).
prove: \\(\triangle fbe \cong \triangle dce\\).

step | statement | reason
1 | abcd is a parallelogram; e is the midpoint of \\(\overline{bc}\\) | given
2 | \\(\overline{be} \cong \overline{ec}\\) | select a reason...

image of parallelogram abcd with e as midpoint of bc, and triangle fbe and dce
note: \\(\overline{df}\\), \\(\overline{af}\\) and \\(\overline{bc}\\) are segments.

answer attempt 1 out of 2
you must answer all questions above in order to submit.

Explanation:

Step1: Recall Midpoint Definition

A midpoint of a segment divides the segment into two congruent segments. Since \( E \) is the midpoint of \( \overline{BC} \), by the definition of a midpoint, \( \overline{BE} \cong \overline{EC} \).

Answer:

Definition of Midpoint (A midpoint of a segment divides the segment into two congruent segments, so since \( E \) is the midpoint of \( \overline{BC} \), \( \overline{BE} \cong \overline{EC} \))