Question

given $k(x) = 8x^3 + 3x$, answer the following:
part: 0 / 4
part 1 of 4
(a) find $k(-x)$.
$k(-x) = \square$

Explanation:

Step1: Substitute $-x$ into $k(x)$

$k(-x)=8(-x)^3 + 3(-x)$

Step2: Simplify each term

$(-x)^3=-x^3$, so $8(-x)^3=-8x^3$; $3(-x)=-3x$

Step3: Combine simplified terms

$k(-x)=-8x^3 - 3x$

Answer:

$k(-x)=-8x^3 - 3x$