QUESTION IMAGE
Question
given: ∠cpn and ∠plh are supplementary
prove: $overleftrightarrow{ck} \parallel overleftrightarrow{fh}$
| statement | reason |
|---|---|
| 2. $square$ | 2. definition of supplementary angles |
| 3. $∠cpn \cong ∠lpk$ | 3. vertical angles theorem |
| 4. $m∠cpn = m∠lpk$ | 4. definition of congruence |
| 5. $square$ | 5. substitution property of equality |
| 6. $square$ | 6. definition of supplementary angles |
| 7. $overleftrightarrow{ck} \parallel overleftrightarrow{fh}$ | 7. $square$ |
Step 1: Analyze Step 2
The reason for step 2 is the definition of supplementary angles, which states that if two angles are supplementary, their measures add up to \(180^\circ\). So for \(\angle CPN\) and \(\angle PLH\) being supplementary, we have \(m\angle CPN + m\angle PLH = 180^\circ\).
Step 2: Analyze Step 5
We know from step 4 that \(m\angle CPN = m\angle LPK\) and from step 2 that \(m\angle CPN + m\angle PLH = 180^\circ\). Using the substitution property of equality (replacing \(m\angle CPN\) with \(m\angle LPK\)), we get \(m\angle LPK + m\angle PLH = 180^\circ\).
Step 3: Analyze Step 6
The reason for step 6 is the definition of supplementary angles, which means that if the sum of two angles' measures is \(180^\circ\), they are supplementary. So from step 5, \(\angle LPK\) and \(\angle PLH\) are supplementary (since \(m\angle LPK + m\angle PLH = 180^\circ\)).
Step 4: Analyze Step 7
To prove \(CK \parallel FH\), we can use the theorem that if two interior angles on the same side of a transversal are supplementary, then the lines are parallel. Here, \(\angle LPK\) and \(\angle PLH\) are same - side interior angles, and since they are supplementary, \(CK \parallel FH\) by the Converse of the Same - Side Interior Angles Theorem.
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
- \(m\angle CPN + m\angle PLH = 180^\circ\)
- \(m\angle LPK + m\angle PLH = 180^\circ\)
- \(\angle LPK\) and \(\angle PLH\) are supplementary
- Converse of the Same - Side Interior Angles Theorem