Question

(a) given $f(x) = 6x^2 + 2|x|$, find $f(-x)$.
$f(-x) = 6(-x)^2 + 2|(-x)|$
$= \square$

Explanation:

Step1: Simplify squared term

$(-x)^2 = x^2$

Step2: Simplify absolute value term

$|-x| = |x|$

Step3: Substitute back to expression

$f(-x)=6x^2 + 2|x|$

Answer:

$6x^2 + 2|x|$