Question

given the function $f(x)=2x^2 - 3x + 1$, complete the table of values for $x$ from $-2$ to $2$.
calculate the corresponding $y$- values for each $x$ - values given.
use the keypad to enter the answers in the boxes.
table of values:

$x$	$-2$	$-1$	$0$	$1$	$2$

Explanation:

Step1: Substitute $x=-2$

$f(-2)=2(-2)^2-3(-2)+1=2(4)+6+1=8+6+1=15$

Step2: Substitute $x=-1$

$f(-1)=2(-1)^2-3(-1)+1=2(1)+3+1=2+3+1=6$

Step3: Substitute $x=0$

$f(0)=2(0)^2-3(0)+1=0-0+1=1$

Step4: Substitute $x=1$

$f(1)=2(1)^2-3(1)+1=2(1)-3+1=2-3+1=0$

Step5: Substitute $x=2$

$f(2)=2(2)^2-3(2)+1=2(4)-6+1=8-6+1=3$

Answer:

$x$	$f(x)$
$-1$	$6$
$0$	$1$
$1$	$0$
$2$	$3$