Question

given right triangle pqr, which represents the value of sin(p)?
○ rp / rq
○ rp / pq
○ rq / pq
○ rq / pr

Explanation:

Step1: Recall sine - ratio definition

In a right - triangle, $\sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}}$.

Step2: Identify opposite and hypotenuse for $\angle P$

For $\angle P$ in right - triangle $PQR$, the opposite side is $RQ$ and the hypotenuse is $PQ$. So, $\sin(P)=\frac{RQ}{PQ}$.

Answer:

$\frac{RQ}{PQ}$ (the third option)