Question

1. graph $-2x + 4y = 4$ for the domain d: ${-8, -4, 0, 4, 8}$.

a. graph a
c. graph c
b. graph b
d. graph d

Explanation:

Step1: Isolate y in the equation

Start by rearranging $-2x + 4y = 4$ to solve for $y$:

$$\begin{align*} 4y &= 2x + 4 \\ y &= \frac{2x + 4}{4} \\ y &= \frac{1}{2}x + 1 \end{align*}$$

Step2: Calculate y for each x in D

Substitute each $x \in \{-8, -4, 0, 4, 8\}$ into $y = \frac{1}{2}x + 1$:

• For $x=-8$: $y = \frac{1}{2}(-8) + 1 = -4 + 1 = -3$
• For $x=-4$: $y = \frac{1}{2}(-4) + 1 = -2 + 1 = -1$
• For $x=0$: $y = \frac{1}{2}(0) + 1 = 0 + 1 = 1$
• For $x=4$: $y = \frac{1}{2}(4) + 1 = 2 + 1 = 3$
• For $x=8$: $y = \frac{1}{2}(8) + 1 = 4 + 1 = 5$

This gives the coordinate pairs: $(-8, -3), (-4, -1), (0, 1), (4, 3), (8, 5)$

Step3: Match to the correct graph

Compare the calculated points to the options. Only option c contains all these points.

Answer:

c. (the graph with points $(-8, -3), (-4, -1), (0, 1), (4, 3), (8, 5)$)