Question

graph each equation.

1. \\(dfrac{x^2}{4} + dfrac{y^2}{9} = 1\\)

Explanation:

Step1: Identify ellipse standard form

The given equation $\frac{x^2}{4} + \frac{y^2}{9} = 1$ matches the vertical major axis ellipse standard form $\frac{x^2}{b^2} + \frac{y^2}{a^2} = 1$ where $a > b$.

Step2: Calculate $a$ and $b$

$a = \sqrt{9} = 3$, $b = \sqrt{4} = 2$

Step3: Find vertices & co-vertices

• Vertical vertices: $(0, \pm a) = (0, 3), (0, -3)$
• Horizontal co-vertices: $(\pm b, 0) = (2, 0), (-2, 0)$

Step4: Plot points and draw ellipse

Plot the 4 points, then sketch a smooth ellipse through them.

Answer:

The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, drawn as a smooth curve connecting these points on the provided coordinate grid.