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QUESTION IMAGE

graph the image of square jklm after a translation 5 units up.

Question

graph the image of square jklm after a translation 5 units up.

Explanation:

Step1: Recall translation rule

For a translation 5 units up, we add 5 to the y - coordinate of each vertex of the square.

Step2: Identify original vertices

Let's assume the coordinates of the vertices of square JKLM are \(J(x_J,y_J)\), \(K(x_K,y_K)\), \(L(x_L,y_L)\), \(M(x_M,y_M)\). From the graph, if \(J\) is at \((- 6,-9)\), \(K\) is at \((-4,-9)\), \(L\) is at \((-4,-8)\) and \(M\) is at \((-6,-8)\).

Step3: Calculate new vertices

For \(J\): The new coordinates are \((x_J,y_J + 5)=(-6,-9 + 5)=(-6,-4)\).
For \(K\): The new coordinates are \((x_K,y_K + 5)=(-4,-9 + 5)=(-4,-4)\).
For \(L\): The new coordinates are \((x_L,y_L + 5)=(-4,-8 + 5)=(-4,-3)\).
For \(M\): The new coordinates are \((x_M,y_M + 5)=(-6,-8 + 5)=(-6,-3)\).

Step4: Graph new square

Plot the new vertices \((-6,-4)\), \((-4,-4)\), \((-4,-3)\) and \((-6,-3)\) on the coordinate - plane and connect them to form the new square.

Answer:

Graph the square with vertices \((-6,-4)\), \((-4,-4)\), \((-4,-3)\) and \((-6,-3)\) on the given coordinate - plane.