Question

graph this line using intercepts:
8x - 8y = 160
click to select points on the graph.

Explanation:

Step1: Find x-intercept (y=0)

Substitute \( y = 0 \) into \( 8x - 8y = 160 \):
\( 8x - 8(0) = 160 \)
\( 8x = 160 \)
\( x = \frac{160}{8} = 20 \)
So, x-intercept is \( (20, 0) \).

Step2: Find y-intercept (x=0)

Substitute \( x = 0 \) into \( 8x - 8y = 160 \):
\( 8(0) - 8y = 160 \)
\( -8y = 160 \)
\( y = \frac{160}{-8} = -20 \)
So, y-intercept is \( (0, -20) \).

Answer:

To graph the line \( 8x - 8y = 160 \) using intercepts, plot the points \( (20, 0) \) (x-intercept) and \( (0, -20) \) (y-intercept), then draw a straight line through them.