Question

graph a right triangle with the two points forming the hypotenuse. using the sides, find the distance between the two points, to the nearest tenth (if necessary). (1,8) and (5, - 1) click twice to draw a line. click a segment to erase it.

Explanation:

Step1: Identify coordinates

Let $(x_1,y_1)=(1,8)$ and $(x_2,y_2)=(5, - 1)$.

Step2: Apply distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.
Substitute the values: $x_2 - x_1=5 - 1 = 4$ and $y_2 - y_1=-1 - 8=-9$.
Then $d=\sqrt{4^2+(-9)^2}=\sqrt{16 + 81}=\sqrt{97}$.

Step3: Calculate the value

$\sqrt{97}\approx9.8$.

Answer:

$9.8$