Question

graphing linear equations
vectored instruction
graph the equation by filling in the chart.
equation: y = 5 - x
(graph with x-axis from -3 to 6, y-axis from -3 to 10, and a table with x values 0,1,2,3,4 and y value 5 for x=0, ? for x=1, etc.)

Explanation:

Step1: Substitute x = 1 into the equation

We have the equation \( y = 5 - x \). When \( x = 1 \), we substitute \( x \) with 1 in the equation.
\( y = 5 - 1 \)

Step2: Calculate the value of y

Simplify the right - hand side of the equation: \( 5-1 = 4 \). So when \( x = 1 \), \( y = 4 \).

For \( x = 2 \):

Step1: Substitute x = 2 into the equation

Substitute \( x = 2 \) into \( y = 5 - x \), we get \( y=5 - 2 \)

Step2: Calculate the value of y

\( 5 - 2=3 \), so when \( x = 2 \), \( y = 3 \)

For \( x = 3 \):

Step1: Substitute x = 3 into the equation

Substitute \( x = 3 \) into \( y = 5 - x \), we get \( y = 5-3 \)

Step2: Calculate the value of y

\( 5 - 3 = 2 \), so when \( x = 3 \), \( y = 2 \)

For \( x = 4 \):

Step1: Substitute x = 4 into the equation

Substitute \( x = 4 \) into \( y = 5 - x \), we get \( y=5 - 4 \)

Step2: Calculate the value of y

\( 5 - 4 = 1 \), so when \( x = 4 \), \( y = 1 \)

Answer:

When \( x = 1 \), \( y = 4 \); when \( x = 2 \), \( y = 3 \); when \( x = 3 \), \( y = 2 \); when \( x = 4 \), \( y = 1 \)

The completed table is:

x	y
1	4
2	3
3	2
4	1