Question

the height of a punted football is approximated by the equation below.
y is the height (in feet) and x is the horizontal distance (in feet) from where the football was punted.
y = -\frac{16}{2025}x^2 + \frac{9}{5}x + \frac{3}{4}
use the numbers as they are shown desmos

1. how high was the football when it was punted?

(hint: when x = 0)
(do not round answers)
use the numbers as they are shown desmos
type a response

Explanation:

Step1: Substitute x=0 into equation

Substitute $x=0$ into $y = -\frac{16}{2025}x^2 + \frac{9}{5}x + \frac{3}{2}$:
$y = -\frac{16}{2025}(0)^2 + \frac{9}{5}(0) + \frac{3}{2}$

Step2: Simplify the expression

Calculate each term:
$y = 0 + 0 + \frac{3}{2}$

Answer:

$\frac{3}{2}$ feet (or 1.5 feet)