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Question
help luca fix his mistake. use the distributive property in reverse to rewrite the expression. $9y + 3 = (3 \cdot 3y) + (3 \cdot 1) = 3(3y + \square)$
Step1: Recall reverse distributive property
The reverse distributive property (factoring) is \(ab + ac = a(b + c)\). Here, \(a = 3\), \(ab=9y\) (so \(b = 3y\)) and \(ac = 3\) (so \(c=\frac{3}{3}=1\)).
Step2: Identify the missing term
We have \(9y + 3=3(3y + \square)\). Since \(3\times\square = 3\), solving for \(\square\) gives \(\square=\frac{3}{3}=1\).
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