Question

how do the areas of the parallelograms compare? the area of parallelogram abcd is 4 square units greater than the area of parallelogram efgh. the area of parallelogram abcd is 2 square units greater than the area of parallelogram efgh. the area of parallelogram abcd is equal to the area of parallelogram efgh. the area of parallelogram abcd is 2 square units less than the area of parallelogram efgh.

Explanation:

Step1: Recall parallelogram area formula

Area = base × height, or $A = b \times h$

Step2: Calculate area of ABCD

Base $AB = 7 - 4 = 3$, height = $6 - 1 = 5$.
$A_{ABCD} = 3 \times 5 = 15$

Step3: Calculate area of EFGH

Base $HE = -2 - (-5) = 3$, height = $6 - 1 = 5$.
$A_{EFGH} = 3 \times 5 = 15$

Step4: Compare the two areas

$A_{ABCD} = A_{EFGH}$

Answer:

The area of parallelogram ABCD is equal to the area of parallelogram EFGH.