Question

how do the areas of the parallelograms compare? the area of parallelogram 1 is 4 square units greater than the area of parallelogram 2 the area of parallelogram 1 is 2 square units greater than the area of parallelogram 2 the area of parallelogram 1 is equal to the area of parallelogram 2 the area of parallelogram 1 is 2 square units less than the area of parallelogram 2

Explanation:

Step1: Recall area formula for parallelogram

The area formula of a parallelogram is $A = base\times height$.

Step2: Count base and height for parallelogram 1

For parallelogram 1, if we consider the base along the horizontal - direction, by counting the grid - squares, the base $b_1 = 4$ units and the height $h_1 = 2$ units. So the area $A_1=b_1\times h_1=4\times2 = 8$ square units.

Step3: Count base and height for parallelogram 2

For parallelogram 2, if we consider the base along the horizontal - direction, the base $b_2 = 4$ units and the height $h_2 = 1$ unit. So the area $A_2=b_2\times h_2=4\times1 = 4$ square units.

Step4: Compare the areas

$A_1 - A_2=8 - 4=4$ square units. So the area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.

Answer:

The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.