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how do the perimeters compare? original 24 in 18 in p = 84 in scaled 12…

Question

how do the perimeters compare? original 24 in 18 in p = 84 in scaled 12 in 9 in p = 42 in the scaled rectangles perimeter is 1/4 the length of the original rectangles perimeter. the scaled rectangles perimeter is 1/2 the length of the original rectangles perimeter.

Explanation:

Step1: Identify given perimeters

Original perimeter $P_{1}=84$ in, scaled - perimeter $P_{2}=42$ in.

Step2: Calculate the ratio

$\frac{P_{2}}{P_{1}}=\frac{42}{84}=\frac{1}{2}$

Answer:

The scaled rectangle's perimeter is 1/2 the length of the original rectangle's perimeter.