Question

how can you write $3^{-2}$ using a positive exponent?
$3^{-2}=$ ?

Explanation:

Step1: Apply negative exponent rule

For any non-zero base $a$ and integer $n$, $a^{-n} = \frac{1}{a^n}$.
For $3^{-2}$, this gives $3^{-2} = \frac{1}{3^2}$

Step2: Simplify positive exponent

Calculate $3^2 = 9$, so $\frac{1}{3^2} = \frac{1}{9}$

Answer:

$\frac{1}{9}$