Question

how can you write $3^{-2}$ using a positive exponent?
$3^{-2} =$
$\frac{1}{3^{3}}$
$\frac{1}{3^{1}}$
$\frac{1}{3^{2}}$
$\frac{1}{3^{3}}$

$3^{n}$	value
$3^{2}$	9
$3^{1}$	3
$3^{0}$	1
$3^{-1}$	$\frac{1}{3}$
$3^{-2}$	$\frac{1}{9}$
$3^{-3}$	$\frac{1}{27}$

Explanation:

Step1: Recall negative exponent rule

For any non-zero base $a$ and integer $n$, $a^{-n} = \frac{1}{a^n}$

Step2: Apply rule to $3^{-2}$

Substitute $a=3$, $n=2$ into the rule:
$3^{-2} = \frac{1}{3^2}$

Answer:

$\frac{1}{3^2}$