Question

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Explanation:

Step1: Eliminate x variable

Multiply first equation by 3:
$3(0.2x + 0.3y) = 3(2)$
$\Rightarrow 0.6x + 0.9y = 6$
Add to second equation:
$(0.6x + 0.9y) + (-0.6x + 1.3y) = 6 + 5$
$\Rightarrow 2.2y = 11$

Step2: Solve for y

Isolate y:
$y = \frac{11}{2.2}$
$\Rightarrow y = 6$

Step3: Substitute y to find x

Plug $y=6$ into first equation:
$0.2x + 0.3(6) = 2$
$\Rightarrow 0.2x + 1.8 = 2$
$\Rightarrow 0.2x = 0.1$
$\Rightarrow x = \frac{0.1}{0.2} = \frac{1}{2}$

Answer:

$x = \frac{1}{2}$, $y = 6$