Question

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Explanation:

1. Rounding Numbers

Step 1: Round 248 to nearest 10 and 100

• Nearest 10: Look at the ones digit (8). Since 8 ≥ 5, we round up. So \( 248 \approx 250 \) (to nearest 10).
• Nearest 100: Look at the tens digit (4). Since 4 < 5, we round down. So \( 248 \approx 200 \) (to nearest 100).

Step 2: Round 983 to nearest 10 and 100

• Nearest 10: Ones digit is 3 < 5, so round down. \( 983 \approx 980 \) (to nearest 10).
• Nearest 100: Tens digit is 8 ≥ 5, so round up. \( 983 \approx 1000 \) (to nearest 100).

Step 3: Round 545 to nearest 10 and 100

• Nearest 10: Ones digit is 5, so round up. \( 545 \approx 550 \) (to nearest 10).
• Nearest 100: Tens digit is 4 < 5, so round down. \( 545 \approx 500 \) (to nearest 100).

2. Finding the Missing Numbers in Subtraction

Step 1: Solve \( \_ - 174 = 85 \)

We know that \( \text{Minuend} = \text{Subtrahend} + \text{Difference} \). So \( \_ = 174 + 85 = 259 \).

Step 2: Solve \( \_ - 197 = 400 \)

Using the same formula, \( \_ = 197 + 400 = 597 \).

3. Dividing Chips Among People

Step 1: Find total number of people

Chris + 5 friends = \( 1 + 5 = 6 \) people.

Step 2: Divide 36 chips by 6 people

\( 36 \div 6 = 6 \). So each person gets 6 chips.

4. Finding Quotients

Step 1: \( 36 \div 4 \)

We know that \( 4 \times 9 = 36 \), so \( 36 \div 4 = 9 \).

Step 2: \( 110 \div 11 \)

\( 11 \times 10 = 110 \), so \( 110 \div 11 = 10 \).

Step 3: \( 27 \div 3 \)

\( 3 \times 9 = 27 \), so \( 27 \div 3 = 9 \).

Step 4: \( 84 \div 12 \)

\( 12 \times 7 = 84 \), so \( 84 \div 12 = 7 \).

5. Missing Factors and Division

Step 1: Find the missing factor in \( 3 \times \_ = 36 \)

We know that \( \_ = 36 \div 3 = 12 \). So the missing factor is 12.

Step 2: \( 36 \div 3 \)

As calculated above, \( 36 \div 3 = 12 \).

6. Cookies Problem

Step 1: Find total number of cookies baked

Henry baked 4 batches of 12 cookies. So total cookies = \( 4 \times 12 = 48 \).

Step 2: Subtract the cookies he ate

He ate 5 cookies. So remaining cookies = \( 48 - 5 = 43 \).

7. Book Dimensions (Area = Length × Width, Area = 88)

We need to find two positive integers \( l \) and \( w \) such that \( l \times w = 88 \).

• Factor pairs of 88: \( (1, 88), (2, 44), (4, 22), (8, 11) \). Assuming reasonable dimensions (like length and width are positive integers and not too large/small), possible dimensions are 8 inches (length) and 11 inches (width) or vice - versa.

Answer:

s:

1. Rounding:

• 248: Nearest 10 = 250, Nearest 100 = 200
• 983: Nearest 10 = 980, Nearest 100 = 1000
• 545: Nearest 10 = 550, Nearest 100 = 500

1. Subtraction:

• \( 259 - 174 = 85 \)
• \( 597 - 197 = 400 \)

1. Chips per person: 6
2. Quotients:

• \( 36 \div 4 = 9 \)
• \( 110 \div 11 = 10 \)
• \( 27 \div 3 = 9 \)
• \( 84 \div 12 = 7 \)

1. Missing factors and division:

• Missing factor: 12, \( 36 \div 3 = 12 \)

1. Cookies left: 43
2. Book dimensions: Length = 8 inches, Width = 11 inches (or Length = 11 inches, Width = 8 inches)