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Question
the hypotenuse of a 45 - 45 - 90 triangle measures 22\sqrt{2} units. what is the length of one leg of the triangle? 11 units 11\sqrt{2} units 22 units 22\sqrt{2} units
Step1: 45-45-90 triangle ratio: hypotenuse = leg×√2
Let leg length be \( l \), hypotenuse \( h = l\sqrt{2} \)
Step2: Substitute hypotenuse value
\( 22\sqrt{2} = l\sqrt{2} \)
Step3: Solve for leg length \( l \)
\( l = \frac{22\sqrt{2}}{\sqrt{2}} = 22 \)
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C. 22 units