Question

identify if the graph is even, odd, or neither.

Explanation:

Step1: Recall even/odd graph rules

An even function's graph is symmetric about the $y$-axis; an odd function's graph is symmetric about the origin.

Step2: Check $y$-axis symmetry

For any point $(x,y)$ on the line, the point $(-x,y)$ is not on the line. Example: $(1,-1)$ is on the line, $(-1,-1)$ is not. So not symmetric about $y$-axis (not even).

Step3: Check origin symmetry

For any point $(x,y)$ on the line, the point $(-x,-y)$ is not on the line. Example: $(1,-1)$ is on the line, $(-1,1)$ is not. So not symmetric about origin (not odd).

Answer:

Neither