Question

ides 2 r - 3 ≤ 2 s + - 1 + 5 ≤ 2 + 3 on the number lines.

Explanation:

Step1: Solve the inequality \( r - 3 \leq 2 \)

To solve for \( r \), we add 3 to both sides of the inequality.
\( r - 3 + 3 \leq 2 + 3 \)
Simplifying both sides, we get \( r \leq 5 \).

Step2: Graph the solution on the number line

• Draw a number line.
• Locate the number 5 on the number line.
• Since the inequality is \( r \leq 5 \), we use a closed circle at 5 (because the inequality includes equality) and shade the line to the left of 5 to represent all numbers less than or equal to 5.

Answer:

The solution to the inequality \( r - 3 \leq 2 \) is \( r \leq 5 \), and it is graphed with a closed circle at 5 and shading to the left on the number line.