Question

ing quadratics by factoring
this is the only question in this section.
olve for all values of $x$ by factoring.
$x^{2}+6x + 1=-2x + 1$

Explanation:

Step1: Rearrange the equation

Move all terms to one - side:
$x^{2}+6x + 1+2x - 1=0$
$x^{2}+8x=0$

Step2: Factor out the common factor

Factor out $x$ from the left - hand side:
$x(x + 8)=0$

Step3: Use the zero - product property

If $ab = 0$, then either $a = 0$ or $b = 0$.
So $x=0$ or $x+8 = 0$

Step4: Solve for $x$

If $x+8 = 0$, then $x=-8$

Answer:

$x = 0$ or $x=-8$