Question

1. if jl = 5x + 2, find jl.

j 27 k 3x - 1 l

Explanation:

Step1: Set up equation for JL

Since $JL = JK+KL$, we have $5x + 2=27+(3x - 1)$.

Step2: Simplify the right - hand side

$5x + 2=27 + 3x-1$, which simplifies to $5x + 2=3x + 26$.

Step3: Isolate x terms

Subtract $3x$ from both sides: $5x-3x + 2=3x-3x + 26$, resulting in $2x+2 = 26$.

Step4: Isolate the constant term

Subtract 2 from both sides: $2x+2 - 2=26 - 2$, giving $2x=24$.

Step5: Solve for x

Divide both sides by 2: $\frac{2x}{2}=\frac{24}{2}$, so $x = 12$.

Step6: Find JL

Substitute $x = 12$ into the expression for JL: $JL=5x + 2=5\times12+2=60 + 2=62$.

Answer:

$62$