Question

kuta software - infinite grade 6 math
distances on the coordinate plane
find the distance between points a and b. state whether you worked with x or y coordinates.
then, show what addition or subtraction expression you used to find the distance.
1)
2)
a(-7,2), b(-7,6)
6 - 2 = 4 units
a(5,-6), b(5,3)

3 - (-6)

=

3 + 6

= 9

3)
4)
a(-6,5), b(-2,5)
2 - (-6) = 4 units
a(-6,-3), b(9,-3)

Explanation:

1) Step1: Identify coordinates

$A(-7, 2)$, $B(-7, 6)$ (same x-coordinate, use y-values)

1) Step2: Calculate vertical distance

$6 - 2 = 4$

2) Step1: Identify coordinates

$A(5, -6)$, $B(5, 3)$ (same x-coordinate, use y-values)

2) Step2: Calculate vertical distance

$|3 - (-6)| = |9| = 9$

3) Step1: Identify coordinates

$A(-6, 5)$, $B(-2, 5)$ (same y-coordinate, use x-values)

3) Step2: Calculate horizontal distance

$|-2 - (-6)| = |4| = 4$

4) Step1: Identify coordinates

$A(-6, -3)$, $B(9, -3)$ (same y-coordinate, use x-values)

4) Step2: Calculate horizontal distance

$|9 - (-6)| = |15| = 15$

Answer:

1. Distance: 4 units; Used y-coordinates; Expression: $6 - 2$
2. Distance: 9 units; Used y-coordinates; Expression: $|3 - (-6)|$
3. Distance: 4 units; Used x-coordinates; Expression: $|-2 - (-6)|$
4. Distance: 15 units; Used x-coordinates; Expression: $|9 - (-6)|$