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the length of a rectangle is 8 feet, and its area is less than 108 squa…

Question

the length of a rectangle is 8 feet, and its area is less than 108 square feet. select an inequality that represents the possible width (w) of the rectangle. then solve the inequality.
108w < 8
108 < 8w
8w < 108
8w + 18 < 108

Explanation:

Step1: Recall area formula

The area $A$ of a rectangle is $A = lw$, where $l$ is length and $w$ is width. Given $l = 8$ feet and $A<168$ square - feet. Substitute into the formula: $8w<168$.

Step2: Solve the inequality

Divide both sides of the inequality $8w < 168$ by 8. Using the property of inequalities, $\frac{8w}{8}<\frac{168}{8}$, which simplifies to $w < 21$.

Answer:

The inequality is $8w<168$ and the solution is $w < 21$. The correct option from the (un - shown) multiple - choice list would be the one with the inequality $8w<168$.