Question

let $f(x)=x^{2}-1$ and $g(x)=9x$. find the following.
$(fg)(0)$

$(fg)(0)=\square$
(simplify your answer.)

Explanation:

Step1: Define $(fg)(x)$

$(fg)(x) = f(x) \cdot g(x)$

Step2: Substitute $x=0$ into $f(x)$

$f(0) = 0^2 - 1 = -1$

Step3: Substitute $x=0$ into $g(x)$

$g(0) = 9 \cdot 0 = 0$

Step4: Calculate $(fg)(0)$

$(fg)(0) = f(0) \cdot g(0)$

Answer:

$0$