Question

1. let $f(x)=\sqrt{x + 1}, g(x)=2x - 5$, and $h(x)=3x^2 - 3$.

find the indicated value.
$f(g(4))=\square$

Explanation:

Step1: Calculate \( g(4) \)

We know that \( g(x) = 2x - 5 \). To find \( g(4) \), we substitute \( x = 4 \) into the function \( g(x) \).
So, \( g(4)=2\times4 - 5 \)
\( g(4)=8 - 5=3 \)

Step2: Calculate \( f(g(4)) \)

Now that we know \( g(4) = 3 \), we need to find \( f(3) \) since \( f(g(4))=f(3) \).
We know that \( f(x)=\sqrt{x + 1} \). Substitute \( x = 3 \) into the function \( f(x) \).
So, \( f(3)=\sqrt{3+ 1} \)
\( f(3)=\sqrt{4}=2 \)

Answer:

\( 2 \)