Question

let $f(x) = -5x - 1$ and $g(x) = x^2 - 1$.
find $(f \circ g)(-2)$.

then $(f \circ g)(-2) = \square$. (simplify your answer.)

Explanation:

Step1: Calculate $g(-2)$

$g(-2) = (-2)^2 - 1 = 4 - 1 = 3$

Step2: Substitute into $f(x)$

$f(g(-2)) = f(3) = -5(3) - 1 = -15 - 1$

Answer:

$-16$