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let $f(x) = 3x^2 + 6x + 9$ and let $g(x) = \\frac{x}{9}$. what is the v…

Question

let $f(x) = 3x^2 + 6x + 9$ and let $g(x) = \frac{x}{9}$. what is the value of $g(f(3))$?
a 1

Explanation:

Step1: Calculate f(3)

Substitute $x=3$ into $f(x)$:
$$f(3)=3(3)^2+6(3)+9=3(9)+18+9=27+18+9=54$$

Step2: Calculate g(f(3))

Substitute $x=54$ into $g(x)$:
$$g(f(3))=g(54)=\frac{54}{9}=6$$

Wait, note: The option A.1 is provided, but based on calculation, the result is 6. However, following the calculation steps strictly:

Answer:

6

(Note: The provided option A.1 does not match the calculated result; the correct value of $g(f(3))$ is 6)